Calculation of the cross-section of DC electrical cables
Manual
Intensity:
2. Example:
The formula to use for copper conductors is:
S = 0.017 x L x I / PT
S = section of the copper conductor expressed in square millimeters
L = outbound + return length of the conductor expressed in meters
I = intensity expressed in Amperes
PT = loss of tension accepted at the level of the cables expressed in
Volts
Manual
Length calculation:
Whatever the nature of the shell, it always requires a "go" or positive conductor in
generally red in color and a "return" or negative conductor in black color.
As specified in Division 240, hull material should never be used as
as a driver.
Intensity:
The nominal intensity is sometimes provided: in this case, nothing could be simpler.
Often, only the power of the device is indicated. In this case, we have to calculate
intensity using the following formula:
P = U x I i.e. I = P / U
P = Power expressed in Watts
U = nominal voltage of the installation (12 V, 24 V or 48 V) expressed in Volts
I = Intensity expressed in Ampere
PT or loss of voltage in the cables:
A current passing through the cables generates a voltage (Ohm's law).
Division 240 specifies that this must remain less than 5% of the rated voltage of
installation either:
Maximum allowed PT in 12 V = 0.6 V (5% of 12 V)
24V = 1.2V (5% of 24V)
Reasonable PT a priori in 12 V = 0.3 V (2.5% of 12 V)
24V=0.6V (2.5% of 12V)
2. Example:
Installation of a 110 W 12 V pump
Distance between the fuse or circuit breaker and the pump via the complete route: 7
meters. Go + return = 14 m.
The nominal current is: 110 / 12 = 9.2 A
The strictly minimum section of the conductor must be:
0.017 x 14 x 9.2 / 0.6 = 3.6 mm²
The so-called “reasonable” section is:
0.017 x 10 x 9.2/0.3 = 7.3 mm²
A section of 4² is sufficient "legally" but a conductor of 6 is preferable.
As far as I am concerned, I prefer to send the maximum voltage to the pumps and I
will carry out the installation in 10²
Manual
Intensity:
2. Example:
The formula to use for copper conductors is:
S = 0.017 x L x I / PT
S = section of the copper conductor expressed in square millimeters
L = outbound + return length of the conductor expressed in meters
I = intensity expressed in Amperes
PT = loss of tension accepted at the level of the cables expressed in
Volts
Manual
Length calculation:
Whatever the nature of the shell, it always requires a "go" or positive conductor in
generally red in color and a "return" or negative conductor in black color.
As specified in Division 240, hull material should never be used as
as a driver.
Intensity:
The nominal intensity is sometimes provided: in this case, nothing could be simpler.
Often, only the power of the device is indicated. In this case, we have to calculate
intensity using the following formula:
P = U x I i.e. I = P / U
P = Power expressed in Watts
U = nominal voltage of the installation (12 V, 24 V or 48 V) expressed in Volts
I = Intensity expressed in Ampere
PT or loss of voltage in the cables:
A current passing through the cables generates a voltage (Ohm's law).
Division 240 specifies that this must remain less than 5% of the rated voltage of
installation either:
Maximum allowed PT in 12 V = 0.6 V (5% of 12 V)
24V = 1.2V (5% of 24V)
Reasonable PT a priori in 12 V = 0.3 V (2.5% of 12 V)
24V=0.6V (2.5% of 12V)
2. Example:
Installation of a 110 W 12 V pump
Distance between the fuse or circuit breaker and the pump via the complete route: 7
meters. Go + return = 14 m.
The nominal current is: 110 / 12 = 9.2 A
The strictly minimum section of the conductor must be:
0.017 x 14 x 9.2 / 0.6 = 3.6 mm²
The so-called “reasonable” section is:
0.017 x 10 x 9.2/0.3 = 7.3 mm²
A section of 4² is sufficient "legally" but a conductor of 6 is preferable.
As far as I am concerned, I prefer to send the maximum voltage to the pumps and I
will carry out the installation in 10²
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